Unit 12
Multi-Step Conditional Reasoning
About this unit
Follow chains of logical rules across multiple steps to determine what must, could, or cannot be true. This unit covers if-then implication chains, set membership overlaps, role assignment under constraints, deductive value assignment, and preference intersection puzzles.
What types of questions will you face?
- 1Implication chains: if A doesn't happen → B → C → D — trace what must follow from a starting condition
- 2Set membership: everyone who likes X likes Y; no one who likes Y likes Z — deduce who likes what
- 3Role/team assignment: 4-5 people need roles filled under a set of conditional constraints — find the valid assignment
- 4Preference intersection: four friends each have food/activity preferences — find the one option all can agree on
- 5Two-statement proofs: choose the two statements that together logically prove a given conclusion
- 6Deductive value assignment: match 5 people to 5 values (scores, prizes, ages) using a set of ordering clues
Skills you will build
- Chaining conditional statements across multiple steps without losing track
- Mapping set membership using inclusion/exclusion diagrams
- Using conditional rules to assign roles under constraints systematically
- Finding the intersection of preference sets by elimination
- Identifying which combinations of statements are logically sufficient
- Handling "if A then B" rules that cascade three or more levels deep
By the end of this unit, you will be able to
- Trace any multi-step if-then chain to its logical conclusion
- Determine what must, could, and cannot be true from a set of premises
- Assign roles and values under complex constraints by systematic elimination
- Find the unique solution satisfying all preference and constraint conditions
Difficulty profile
Medium difficulty (avg 3.26). Simple 2-step chains are Easy; set membership deductions are Medium; multi-person role/value assignment under multiple conditional rules is Difficult. This is one of the most intellectually demanding unit types.
Exam tip: Multi-Step Conditional Reasoning
Build a table or diagram as you read. For chain problems, trace forward from the given starting condition one step at a time. For role assignments, start with the person who has the fewest valid options and place them first.
Sample Questions
Camp-activity survey questions look wordy, but they are really set puzzles: chain the “everyone who…” rules, then count who can land in each circle.
Nested preference / overlap items appear in the easy band of Selective TS — strong marks when you sketch overlapping groups instead of guessing from the options.
The examiner checks whether you can translate “all A are B”, “no A and C together”, and “more only-X than only-Y” into a consistent Venn picture and infer which activity has the largest audience.
A survey lists several activities and rules about who likes what together or apart. You choose which activity was most popular (or which scenario is forced).
Best approach: Draw one circle per activity. Stack the chains (Harving → Glinting → Kelrish). Mark forbidden overlaps (Mortay ∩ Glinting = ∅). The biggest circle — usually the one everything else feeds into — is the answer.
Question
A school surveyed all its students about which of four traditional camp activities they enjoyed: Glinting, Harving, Kelrish, and Mortay. The survey found the following:
- Everyone who liked Glinting also liked Kelrish.
- Everyone who liked Harving also liked Glinting.
- No one liked both Mortay and Glinting.
- Some students liked both Kelrish and Mortay.
- There were more students who only liked Kelrish than students who only liked Mortay.
Which activity was most popular?
- AGlinting
- BHarving
- CKelrish
- DMortay
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Age-chain puzzles give you one concrete number and a series of "older/younger by" clues — follow the chain and fill in every age before touching the answer choices.
Deductive age-assignment questions appear in the easy-to-medium band of official NSW papers — they are reliable marks when you build a summary table and verify every option against it.
The examiner checks whether you can follow a chain of relative-age clues from a single anchor value, complete the full table, and identify the one true statement among four carefully crafted distractors.
Five or six children are related by age clues (twins, older by N years, younger by N years, between two ages). One concrete age is given. You find all ages, then test which of four statements is the only true one.
Best approach: Start from the one clue that gives a real number (e.g. Brian = 8). Use each other clue as a stepping stone to the next person. Build a name → age table. Only then check every option against your table — do not guess based on the first option that sounds right.
Question
The children Anita, Brian, Eric, Lee and Zara are all in one family. Lee is 1 year younger than Eric. Brian and Eric are twins. Anita is 3 years older than Lee. Brian is 8 years old. Zara is older than Eric, but younger than Anita.
Only one of these sentences is true. Which is it?
- AEric is 11.
- BAnita is 2 years older than Zara.
- CAll the children are 8 or older.
- DAnita is 10.
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Four students, four positions in a race — and Stephen gets no clue of his own. But pin down Bruce (last), then Ethan (2nd), then James (3rd) one by one, and Stephen's 1st place is the only spot remaining.
Simple elimination ordering questions appear at the easier end of NSW Selective TS — they are reliable early-paper marks for students who work through clues methodically instead of guessing.
The examiner checks whether students can identify which clues give definite positions ('no one after X' = last; 'only one before X' = 2nd), chain them in the right order, and find the unmentioned person's position by elimination.
Four (or five) people in a race or ranking. Each clue pins down one person's position. One person is never directly mentioned in any clue — their position is found last by elimination. The options are the four possible finishing positions.
Best approach: Start with the clue that gives a fixed position directly: 'no one after X' = last; 'only one before X' = 2nd. Fill in the table. Then chain from Ethan's position to James's. The person with no direct clue (Stephen) gets whatever position is left. Always double-check by re-reading all clues against your final table.
Question
Four students had a race to see who could get to the top of the hill and back first.
No one arrived back after Bruce.
Only one person was faster than Ethan.
James finished after Ethan.
Where did Stephen finish?
- A1st
- B2nd
- C3rd
- D4th
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Four shops sell the same TV at different prices. Nathan wants the fastest delivery but can't afford the priciest. Two ordered lists — one for price, one for speed — are all you need to find his answer.
Multi-attribute ordering questions (two attributes: speed + price, or height + weight, etc.) appear regularly in NSW Selective TS. They often use a constraint to eliminate one or more options before the final ranking comparison.
The examiner checks whether students can build two separate ordered lists from scattered clues, apply a hard constraint (eliminate the most expensive) correctly, and then rank the remaining options on the second attribute.
Four or five items are compared on two attributes (e.g. delivery speed and price). A character has a preference for one attribute and a constraint on another. Students build each list from comparative clues and apply the constraint to find the answer.
Best approach: Build each list separately. Price clues: Roberts < Brennan < KX Hi-Fi < Hughes Home. Hughes Home is most expensive → eliminated. Speed clues: Brennan Audio fastest, then KX Hi-Fi, then Roberts Electrical. Among the remaining three, Brennan Audio wins on speed. Always apply the constraint (eliminate) before picking the winner.
Question
Four online shops – Hughes Home, KX Hi-Fi, Brennan Audio, and Roberts Electrical – are all selling the same model of television but at different prices. Nathan needs to get one as quickly as possible but can’t afford the most expensive.
KX Hi-Fi takes longer to deliver than Brennan Audio, but is faster than Roberts Electrical. Roberts Electrical is cheaper than Brennan Audio. KX Hi-Fi costs more than Brennan Audio, but is cheaper than Hughes Home.
Which of the four shops will Nathan choose?
- AHughes Home
- BKX Hi-Fi
- CBrennan Audio
- DRoberts Electrical
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A train travels from Jaspur to Salumbar with four stops in between. Three clues tell you the relative order of the stops. Jennifer gets off at the second-last station — but two different orderings are valid. Does it matter which one is correct?
Linear ordering questions with a 'between' clue appear regularly in NSW Selective TS. The key skill is chaining 'before/after' clues first, then slotting 'between' items. When two orderings are possible, check whether the target position (second-last, first, etc.) is the same in both — often it is, giving a unique answer.
The examiner tests whether students can (a) chain Clues 2 and 3 to get Wadi → Anjar → Gadarpur, (b) recognise that Kavali can slot in at two positions without changing Gadarpur's last-place status, and (c) conclude that the second-last station is always Gadarpur regardless of Kavali's position.
A journey has N stops between start and end. Three or four clues give pairwise 'before' and 'between' relationships. One or two positions can't be pinned down uniquely. A question asks for the position of one specific station — which turns out to be anchored by the clues even when the full order isn't unique.
Best approach: Chain the 'before' clues first: Wadi → Anjar → Gadarpur. Then apply the 'between' clue: Kavali is between Wadi and Gadarpur, so it slots in at position 2 or 3 of the four intermediate stops. In both cases, Gadarpur is last (4th). The second-last station is always Gadarpur.
Question
The train journey from Jaspur to Salumbar stops at four other stations along the way. Jennifer boarded the train at Jaspur and got off at the second-last station.
Kavali station is located between Wadi and Gadarpur.
The train stops at Wadi before Anjar.
The train stops at Anjar before Gadarpur.
Which station did Jennifer get off at?
- AAnjar
- BKavali
- CWadi
- DGadarpur
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When a rule has two different tracks depending on a person's situation, the first step is always to identify which track applies — then the only failure reason is whatever that track requires.
Eligibility rule questions with branching conditions appear regularly in the harder half of NSW Selective TS papers — they reward students who slow down, map the tracks clearly, and apply only the relevant rule.
The examiner tests whether you can parse a multi-branch conditional rule, identify which branch applies to a named person, and deduce the one necessary reason for their failure — not confuse requirements from the wrong branch.
An institution has two sets of entry requirements depending on whether an applicant has a certain qualification. A named person with that qualification fails. The question asks what must have been the reason — the answer is always the specific failure in their (simpler) branch.
Best approach: Step 1: identify which rule applies to this person. Step 2: list only the requirements for that rule. Step 3: the reason they failed must be the one requirement they didn't meet. Ignore all conditions from the other branch entirely.
Question
Jun's school was selecting students for a new course in computer programming. As well as considering their existing knowledge of computer programming, the school set them a maths test and a chess challenge.
If a student had at least some existing knowledge of programming, then they only had to pass the maths test. If they had none, then they either needed to get an excellent score on the maths test, or do well in both the maths test and the chess challenge.
Jun is an experienced computer programmer but failed to get a place on the course. What must have been the reason?
- AHe did badly in the chess challenge.
- BHe did not get an excellent score in maths.
- CHe failed his maths test.
- DHe did badly in both maths and chess.
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The trick is in the words: "likely" and "might" leave gaps where exceptions can slip through — but "will not" and "doesn't stand a chance" are absolute. The impossible scenario is always the one that breaks a certain rule.
Multi-rule conditional chain questions with mixed certainty words appear in the harder band of NSW Selective TS — the examiner is specifically testing whether you notice the difference between probable and certain.
The examiner tests whether students can distinguish probabilistic language ('likely', 'might') from certain language ('will not', 'no chance') in a chain of conditionals, and use that distinction to identify which scenario is logically impossible.
Three or four if-then statements are given. Some use certain language ('will not'), some use uncertain language ('likely', 'might'). The question asks which scenario is NOT possible. The impossible option breaks a CERTAIN rule; the possible options rely on the uncertain gaps.
Best approach: Before reading the options, annotate each rule as CERTAIN or UNCERTAIN. Then test each option: does it require breaking a certain rule? If yes, it's impossible. If it only requires an uncertain rule to not fire (which is allowed), it's possible.
Question
If Monti does not sleep well, then he's likely to be tired.
If he is tired, then he will not perform well at the interview.
If he performs well at the interview, then he might be offered the job. Otherwise he doesn't stand a chance.
If the above statements are correct, which one of the following is not possible?
- AMonti did not sleep well but got the job.
- BMonti slept well but did not get the job.
- CMonti performed well at interview but did not get offered the job.
- DMonti was tired at the interview but still did well enough to get the job.
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A substitution cipher maps 26 letters to only 10 digits — so several letters must share each digit. Gabi encodes four words. Luke decodes three with confidence. One word he can't be sure about. Why? Because its digit sequence also spells a different real word.
Code/cipher ambiguity questions appear occasionally in NSW Selective TS. They combine cipher-reading skills with the ability to systematically test alternative decodings — a neat crossover of logical and linguistic reasoning.
The examiner checks whether students can (a) correctly apply a repeating letter-to-digit mapping, (b) identify which digits have multiple letter options, and (c) check systematically whether any alternative letter combination from those options forms another real English word.
A cipher maps letters to digits (with repeats). Four encoded words are decoded. Students must identify which decoded word could also be decoded as a different real word — creating genuine ambiguity for the decoder.
Best approach: First note which digits are shared by multiple letters (here all digits 0-9 map to 2-3 letters each). Encode each word and then substitute alternative letters for each digit. For DONE (4-5-4-5): digit 4 = D or N or X; digit 5 = E, O, or Y. Swapping D→N and N→N gives NONE (4-5-4-5) — a real word with the same code. The others (TOOK, HIGH, SORT) have no common-word alternatives.
Question
Gabi and Luke want to use a code to send secret messages to each other. In the code, each letter of the alphabet is represented by a one-digit number, as follows:
| A | B | C | D | E | F | G | H | I | J |
|---|---|---|---|---|---|---|---|---|---|
| 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 0 |
| K | L | M | N | O | P | Q | R | S | T |
|---|---|---|---|---|---|---|---|---|---|
| 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 0 |
| U | V | W | X | Y | Z |
|---|---|---|---|---|---|
| 1 | 2 | 3 | 4 | 5 | 6 |
For example, the word BELL would be written in the code as 2-5-2-2.
To test the system, Gabi writes four words in the code and sends them to Luke. Luke tries to decode them, and gets the following answers:
TOOK
DONE
HIGH
SORT
Luke is confident that he has three of these words correct, but he is unsure about the other one.
Which word is Luke unsure about?
- ATOOK
- BDONE
- CHIGH
- DSORT
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Four people entered last year's pie-eating contest. One finished last. One finished worse than she did the year before. And the winner two years ago can't win again. Strip away the positions one by one — who's left for 2nd?
Contest/ranking elimination questions are a regular feature of NSW Selective TS deductive reasoning. They combine a 'no-repeat' rule with comparative clues ('didn't do as well') to pin down one specific position through elimination.
The examiner checks whether students can (a) apply the 'different winner each year' rule to eliminate Mr Green from 1st, (b) interpret 'didn't do as well' as a strict worsening of position, and (c) use process of elimination to fill the final remaining spot.
Several people competed in a ranked contest. A few clues fix specific positions (who finished last, who did worse than before). A background rule eliminates another candidate from a specific position. The remaining position is determined by elimination.
Best approach: Start with the most certain clues. Ms White = last (4th). Mrs Black did worse than 2nd but Ms White has 4th, so Mrs Black = 3rd. Apply the no-repeat rule: Mr Green won two years ago → cannot win again → Miss Orange wins (1st). The only position left for Mr Green = 2nd (runner-up).
Question
For the last five years, the Colby Street pie-eating contest has been won by a different person every year. Two years ago, the winner was Mr Green, and Mrs Black was runner-up.
Last year, four contestants entered: Mr Green, Mrs Black, Miss Orange, and Ms White.
Ms White had no appetite and finished last.
Mrs Black started well but didn’t do as well as she had the previous year.
Who was last year’s runner-up?
- AMr Green
- BMrs Black
- CMiss Orange
- DMs White
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Three suspects, one guilty. Each makes a statement. But only one is telling the truth. Whose statement is true? Whose is a lie? You need to test each scenario — only one arrangement produces exactly one truth-teller.
Truth-teller and liar puzzles appear consistently on NSW Selective TS Deductive Reasoning. They seem complex but are completely mechanical: test each scenario, count truth-tellers, and eliminate those that violate the constraint.
The examiner tests whether students can (a) set up all possible scenarios for who is guilty, (b) evaluate each statement as true or false under each scenario, (c) count truth-tellers and discard scenarios that don't produce exactly the required number, and (d) read off what must be true from the surviving scenario.
Three or more people each make a statement. A constraint specifies exactly how many are telling the truth. Only one person can be guilty/correct/first, etc. Students must find the unique valid scenario and identify which answer option is consistent with it.
Best approach: Build a table: rows = scenarios (who is guilty), columns = each person's statement. Mark each statement TRUE or FALSE for each scenario. Count truth-tellers per row. Keep only the row with the right number of truth-tellers. Then check each answer option against the surviving row.
Question
Three men – Arthur, Bobby and Darren – are suspects in a crime investigation. Only one man is guilty. When they are questioned, they give the following statements:
Darren: “Bobby is guilty.” Bobby: “I am not guilty.” Arthur: “I am not guilty.”
However, only one of the three men is telling the truth; the other two are lying.
Which one of the following statements must be true?
- ADarren is guilty.
- BBobby is lying.
- CArthur is not guilty.
- DDarren is lying.
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Tim has read Noon. Three rules tell us things about Morning and Night readers — but all three rules point TOWARD Noon, not FROM it. Can we use those rules to say anything about what Tim has read?
The affirming-the-consequent trap is one of the most frequently tested logical errors in NSW Selective TS. Students see that 'if P then Q' is true and Q is true, and incorrectly conclude P must be true. These questions appear across books, languages, group membership, and survey results.
The examiner checks whether students recognise that if-then rules only run in one direction. Knowing the 'then' part is true (Tim read Noon) gives us ZERO information about the 'if' part (whether he read Morning or Night). The correct answer is 'we cannot determine' — not because information is missing, but because the rules simply don't work backwards.
A set of if-then rules all point toward a common outcome (reading Noon, being in a club, passing a test). A student is told someone has that outcome and asked what we can conclude. The trick: the rules go toward the outcome; we can't infer anything from knowing the outcome alone. Multiple scenarios remain valid.
Best approach: Write each rule as 'if P then Q' and identify which part you are told (P or Q). If you are told Q (the 'then' part), none of the rules can fire in reverse. Enumerate the possible scenarios by asking: what are all the valid combinations? Show at least two that are consistent with the given information but lead to different answers. This proves 'we cannot know.'
Question
A famous author has written three children’s books. The titles are: Morning, Noon, and Night. Year 5 did a survey to discover which of the books was most popular in the class. It was found that:
- All the children who had read Morning had also read Noon.
- Most of the children who had read Morning had also read Night.
- No child had read Night who had not read Noon.
We know that Tim has read Noon. Which one of the following statements is true?
- AWe know that he has read Morning, but has not read Night.
- BWe know that he has read Night, but has not read Morning.
- CWe know that he has read both Morning and Night.
- DWe do not know whether he has read either Morning or Night.
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Four students competed to read the most books. Three clues narrow down the ranking — but not completely. Two valid orderings remain. Which statement is true in BOTH of them?
'What must be true?' ranking questions appear regularly on NSW Selective TS. They are harder than full-order deductions because the ranking is only partially determined, and students must test each answer option against every valid arrangement — not just one.
The examiner checks whether students can (a) fix Carlos at 2nd using the 'exactly two below' clue, (b) prove Bryan is always 4th by eliminating his other possible positions, (c) enumerate the two valid arrangements for Olivia and Sharon, and (d) recognise that only option A holds in both, while options C and D only hold in one arrangement.
Four people are ranked using clues about relative order ('fewer than', 'more than', 'did not finish last'). One clue fixes one person's position exactly. Another clue eliminates one person from the top. The full order can't be determined, but one pairwise relationship is guaranteed in every valid arrangement.
Best approach: Step 1: Fix positions you can determine fully (Carlos = 2nd from Clue 2). Step 2: Prove Bryan is always last by showing he cannot be 3rd (Olivia can't be 4th) and cannot be 1st (would be above Sharon). Step 3: List all valid arrangements for the uncertain spots. Step 4: Test each option against ALL valid arrangements. Keep the one that's true in every arrangement.
Question
Four students had a competition to see who could read the most books.
Olivia did not read the fewest books.
Only two people read fewer books than Carlos.
Bryan read fewer books than Sharon.
Which one of the following must also be true?
- ACarlos read more books than Bryan.
- BBryan read more books than Carlos.
- CCarlos read more books than Sharon.
- DSharon read more books than Carlos.
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Four parrots, three rules about what they eat. Which conclusion must follow? Three of the options commit the inverse or converse fallacy. Only one chains two contrapositives correctly.
Multi-rule 'what must be true?' questions appear in every NSW Selective TS paper. The key skill is finding the contrapositive of each rule and then chaining rules together. The three wrong options always test the inverse and converse errors — recognising these patterns makes elimination fast.
The examiner tests whether students can (a) write the contrapositive of Rule 3 (eats peas → no carrots) and Rule 1 (no carrots → no apples), (b) chain them to get 'eats peas → no apples', and (c) recognise that Options A, B, D each commit a classic fallacy (converse or inverse) while Option C is the valid two-step chain.
Three if-then rules create a chain (apples → carrots → melons) plus a blocking rule (carrots → no peas). Four options test: forward use (often wrong direction), inverse (wrong), converse (wrong), and the valid contrapositive chain (correct). The correct answer always involves chaining two contrapositives.
Best approach: Write each rule's contrapositive. Look for a chain: Rule 3 contra. (peas → no carrots) + Rule 1 contra. (no carrots → no apples) = peas → no apples. That's Option C. For the others: check if the direction is valid (forward or contrapositive only). Options B and D use inverse/converse — eliminate them.
Question
A bird sanctuary has four parrots: Cliff, Echo, Muse, and Sky. Staff at the sanctuary are keeping track of the treats the parrots like to eat.
They have found that if a parrot eats apples, it also eats carrots. If a parrot eats carrots, it also eats melons. No parrot that eats carrots also eats peas.
Based on the above information, which one of the following must be true?
- AIf Cliff eats peas, he also eats apples.
- BIf Echo does not eat peas, he does not eat carrots.
- CIf Muse eats peas, she does not eat apples.
- DIf Sky does not eat apples, she does not eat carrots.
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Semester pass/fail chains are the Selective version of “must be true” logic: each rule is an arrow, and one option breaks a rule no matter how you try.
Multi-subject conditional grids sit in the difficult band of Selective mocks — the same trap as conditional syllogisms: you cannot assume two groups overlap just because they share a parent set.
You must test each Sara scenario against every rule (English → Geography, IT → History, no Geography+IT together) and eliminate the outcome that is impossible, not merely unlikely.
Several if-then rules about exam results are given, plus global facts (no one failed all four, no one passed all four). Four complete result patterns for one student are offered; one cannot happen.
Best approach: Take one option at a time. Apply forward implications first (pass English → must pass Geography). Check mutual exclusions (Geography vs IT). The wrong pattern is the one that forces a contradiction.
Question
In semester tests, students took English, Geography, History, and IT. The following results were achieved by the class:
- Everyone who passed English also passed Geography.
- Everyone who passed IT also passed History.
- No one passed both Geography and IT.
- No one failed all four subjects.
- No one passed all four subjects.
Which one of the following is not possible?
- ASara passed English and Geography, but failed History and IT.
- BSara passed English and IT, but failed History and Geography.
- CSara passed History and Geography, but failed English and IT.
- DSara failed English and IT, but passed Geography and History.
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Three friends take turns rolling a dice and swapping marbles. By the end you know everyone's total — but you have to work backwards to figure out the last roll.
Three-player marble (or counter) token-swap questions appear in the harder band of Selective TS papers — they test whether you can track state changes across multiple turns rather than just reading off a final answer.
The examiner wants you to simulate each turn in order, update all three players' totals correctly, and then reverse-engineer the unknown roll from the difference between the second-last state and the final totals.
Three players each start with the same number of tokens. A dice roll is even → that player gives the rolled amount to each other player. Odd → they receive it from each. Two rolls are given; you must find the third.
Best approach: Build a three-column table (one column per player) and fill in each row after every roll. After both known rolls are applied, compare each player's running total to their given final total. The difference tells you both the odd/even type and the value of the unknown roll.
Question
Kai, Joe and Alice have 30 marbles each.
They take it in turns to roll a dice.
- If the number rolled is even, then that player has to give the number of marbles shown on the face of the dice to each of the other two players.
- If the number rolled is odd, then that player receives the number of marbles shown on the face of the dice from each of the other two players.
Kai rolls a 5.
Joe rolls a 2.
If the friends end up with 41, 20 and 29 marbles respectively, which number does Alice roll?
- A1
- B2
- C3
- D4
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Five houses, five people, five sports, five transports — and eight clues to untangle them. The secret is to start with the clues that give you exact positions, then use contradictions to eliminate wrong arrangements.
Five-in-a-row grid puzzles appear in the harder half of NSW Selective TS papers and are worth nailing — once you have a system, they are very reliable marks.
The examiner tests whether you can manage multiple attributes across ordered positions simultaneously, using distance clues and attribute clues in combination without getting confused.
Five people sit or live in a row. Each person has two or three unique attributes (sport, transport, colour, etc.). Clues mix position clues (left end, middle, next to, two spaces from) with attribute clues (likes X, drives Y). One question asks who is in a specific position.
Best approach: Start by placing anyone given an absolute position (left end, right end, middle). Then test distance clues by writing out a small table of possibilities and cross off any that contradict an attribute clue. Fill in remaining attributes (sport, transport) one by one once positions are locked.
Question
Five houses stand together in a row. One person lives in each house; each person likes a different sport; they all use different forms of transport. We also know that:
- Mr Green likes tennis and lives next to Ms White, who is on the left end of the row and drives a van.
- Dr Grey uses a taxi.
- The person who likes badminton lives in the middle of the row.
- Miss Orange drives a car and doesn't like swimming.
- The person who likes swimming does not have a motorcycle.
- Mrs Black likes football; she lives next to Miss Orange and two spaces from Dr Grey.
- The person who rides a bicycle also likes football.
- The person who likes golf lives next to the person who likes badminton.
Using the information above, who lives in the last house on the right of the row?
- ADr Grey
- BMiss Orange
- CMrs Black
- DMr Green
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Three survey rules, four options — three of them use the rules backwards or in reverse. The only answer that works traces a clean two-step chain: Volleyball → Skiing → NOT Gymnastics.
Multi-rule 'must be true' questions with sport/activity survey setups appear in the harder half of NSW Selective TS and are excellent marks for students who know to test both direct and chained deductions.
The examiner tests whether students can follow a chain of two rules to derive a valid conclusion, while rejecting options that use rules in the wrong direction (converse and inverse errors) — common and well-disguised traps.
A survey or group describes three or four 'everyone who X does Y' rules. Options present conditional statements about one of the named individuals. Only one option follows directly from the rules (or from chaining two of them); the rest reverse or misapply the rules.
Best approach: List each rule as 'If X → Y.' For each option, trace whether it flows in the same direction as a rule or a chain of rules. Reject options that read rules backwards (converse: Y → X) or in reverse-negative (inverse: NOT X → NOT Y). The correct option must trace cleanly through the rules.
Question
In a survey of television viewers, everyone who liked volleyball liked skiing. Everyone who liked skiing liked cycling, but no one who liked skiing liked gymnastics.
Darren, Amanda, Lee and Jess all took part in the survey.
Based on the information, which one of the following must be true?
- AIf Darren likes cycling, he also likes skiing.
- BIf Amanda does not like gymnastics, she does not like cycling.
- CIf Lee does not like volleyball, he does not like skiing.
- DIf Jess likes volleyball, she does not like gymnastics.
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Five children, two rankings to track — speed and accuracy. Most options could go either way, but one directly contradicts a fact you can prove. The moment you fix Hailey as 1st, the impossible option jumps out.
'Cannot be true' questions with two parallel rankings (speed + correctness) appear in the harder half of NSW Selective TS and reward students who build both ordered lists before checking the options.
The examiner tests whether students can extract two separate rankings from interconnected clues, then correctly identify the one option that contradicts a provable fact — rather than guessing from instinct.
A set of 4–6 clues about a group gives partial ordering information across two or more attributes (e.g. speed and score). One option contradicts a ranking you can prove with certainty; the others are either true or could be true.
Best approach: Make two tables: one for speed/order, one for correct answers. Fill in what you know with certainty first (Adam last, Natalie 2nd). Chain the remaining clues to pin down Hailey. Then test each option against your tables — the impossible one contradicts a definite entry.
Question
Five children did a test with five difficult questions to answer.
- Hailey was faster than Gabriella, but got three questions wrong.
- Adam got all the questions right, but took the longest.
- Natalie finished second, but got two questions wrong.
- Gabriella got more questions right than Natalie, but finished after her.
- Kamilla wasn't as fast as Natalie, but Natalie was not as fast as Hailey.
If all the above statements are true, only one of the sentences below cannot be true. Which one?
- AGabriella got fewer questions right than Adam.
- BHailey was faster than Kamilla.
- CHailey was not first to finish.
- DHailey got fewest questions right.
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Four games, five clues about who likes what — and you have to figure out which game is most popular without a single number in sight. The key is realising that Koolchee quietly absorbs everyone else's fans.
Set-relationship questions with 'which group is largest?' conclusions appear in the harder section of NSW Selective TS — they reward students who can chain subset clues (A ⊆ B ⊆ C) to reach a size comparison without needing actual numbers.
The examiner tests whether students can build a mental Venn diagram from verbal clues — identifying subsets, exclusions, and overlaps — and then use those relationships to determine which group must be the biggest.
Four named groups are given. Clues describe subset relationships (everyone in A is also in B), exclusions (no one in A is in C), overlaps (some in A are also in D), and size comparisons (more in X-only than Y-only). The correct group is the one that all others feed into, plus has its own extras.
Best approach: Draw four circles and sketch each clue: arrows for subsets ('everyone in A is in B'), crossed circles for exclusions ('no overlap'), dotted overlaps for partial sharing. Then count which circle absorbs the most other circles' fans. The game that contains other games' fans as subsets, and also has unique fans of its own via an overlap clue, is the most popular.
Question
Brook and Joyce wanted to find out which was the most popular traditional game at their school: Wulijini, Buroinjin, Koolchee or Keentan. They did a survey of all the students at the school, and found the following:
- Everyone who liked Wulijini also liked Koolchee.
- Some people liked both Koolchee and Buroinjin.
- No one liked both Buroinjin and Wulijini.
- There were more people who only liked Koolchee than people who only liked Buroinjin.
- All the Keentan fans were also fans of Wulijini.
Which was the most popular game?
- AWulijini
- BKoolchee
- CBuroinjin
- DKeentan
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Runners, swimmers, gymnasts — three clues about who beats whom, and four tricky conclusions to evaluate. The surprise: most runners sit BELOW the gymnasts, yet the top runner beats everyone. That gap is what makes runners' range the widest.
'Which conclusion follows?' questions with partial ordering clues and range comparisons appear in the harder section of NSW Selective TS — they reward students who map out the full picture before evaluating any option.
The examiner tests whether students can (a) build a complete ordering from three partial clues, (b) reason about ranges (not just averages), and (c) resist options that sound plausible but contradict one of the clues (especially option C which flips clue 2).
Three groups have overlapping ordering clues: one group's TOP beats another group's TOP; one group beats MOST (not all) of another group; one group beats ALL of a third. Students must determine which conclusion is guaranteed — usually about ranges, not averages.
Best approach: Draw a horizontal fitness line. Place each group using the clues: all gymnasts above most runners, all swimmers above all gymnasts, fittest runner above fittest swimmer. Identify where each group starts and ends on the line. The group that spans the widest section — from its lowest to its highest — has the greatest range. Eliminate options that require average calculations (can't conclude) or that contradict given clues.
Question
Muhammad’s school wanted to find out how different sports affected people’s fitness levels. They made all the best sports people take a fitness test. This is what they found:
- The fittest runners were fitter than the fittest swimmers.
- All the gymnasts were fitter than most of the runners.
- All the swimmers were fitter than all the gymnasts.
Which one of these sentences can be concluded from the above information?
- AThe swimmers’ average fitness levels were better than that of the other groups.
- BThe range of fitness levels was the greatest amongst the runners.
- CRunners and swimmers will generally be fitter than gymnasts.
- DThere was less of a range of fitness levels amongst the gymnasts than amongst the swimmers.
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The sports coach is opening the hall on a school morning. That one observation, combined with four simple rules about who does what and when, leads to only one possible conclusion — but students who rush will pick a trap answer.
'Which must be correct?' questions with scheduling or role-based rules appear regularly in NSW Selective TS. They reward students who build a mental map of all the rules before evaluating each option.
The examiner checks whether students can chain multiple conditional rules together, use morning/afternoon timing to narrow possibilities, and resist options that are merely possible (not necessarily true).
A scenario describes people with different roles and schedules. One specific situation is observed. Students determine which of four conclusions must be true, using all rules together.
Best approach: List all rules first. Note what the observation tells you (morning + sports coach opening). Use the morning/afternoon timing rule: morning opening by sports coach = training. From training = no event today (same-day rule). Then test each option: does it HAVE to be true, or is it just possible? Cross out anything that is only maybe true.
Question
You arrived at school this morning and saw the sports coach opening the sports hall.
The cleaner opens the hall every day except Sundays and Mondays, when the hall either remains closed or is opened by the sports coach. The sports coach is only there for training and for competitive events. The hall is reserved for training in the mornings and events in the afternoons.
The sports coach always arrives fifteen minutes early for both training and events, and schedules them to make sure that they do not occur on the same day.
Which one of the following sentences must be correct?
- AToday is Sunday.
- BThe hall is open for training today.
- CThere is a competitive event today.
- DThe cleaner is unexpectedly away.
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A school play has three conditional rules: ticket sales determine whether it goes ahead, working hard determines whether it succeeds, and success determines whether there will ever be a next play. Which outcome is logically impossible?
'Which is NOT possible?' questions are a premium variant of conditional-logic problems in NSW Selective TS. Instead of finding what must be true, you must find the one option that CANNOT happen under any circumstances — worth practising because students often confuse 'unlikely' with 'impossible'.
The examiner tests whether students can apply contrapositives: if the principal allows another play, the play must have been a success; if the play was a success, all must have worked hard and learned their lines. Chaining these together reveals that 'another play despite not learning lines' is a contradiction.
Three or more if-then rules create a chain of consequences. Four outcomes are offered; three are possible under some scenario, one directly contradicts the chain. The trap is confusing 'X doesn't guarantee Y' (so Y might not happen) with 'X prevents Y' (so Y is impossible).
Best approach: Write each rule as 'if P then Q', then find its contrapositive ('if not Q then not P'). For the 'not possible' option, build the chain from the option backwards: what must be true for the principal to allow another play? Trace back through the rules until you hit a contradiction. For the other options, confirm the rules DON'T guarantee the opposite of what the option says.
Question
If we don’t sell three quarters of the tickets then the school play will be cancelled.
If the play goes ahead and we make it a success, then we might just be able to convince the principal to let us put on another play next summer. It won’t be a success, though, if people don’t work hard and learn their lines.
If the play is not a success, then it will be the last play we are allowed to do.
Which one of the following outcomes is not possible?
- AThe play did not go ahead even though they sold all the tickets.
- BThe play did not go ahead even though they all worked hard and learned their lines.
- CThe play was not a success even though they all worked hard and learned their lines.
- DThe principal let them put on another play even though they didn’t all learn their lines.
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Four rules govern who passed Maths, Physics and Computing. One of them says passing Maths forces you to pass Computing too. Another says no one passed all three. Together, those two rules make one particular combination impossible — but which one?
'Which is NOT possible?' questions using overlapping pass/fail rules are a top-tier Selective TS question type. They demand systematic rule-checking across all combinations — usually rewarding students who build a complete valid/invalid table rather than guessing from the options.
The examiner checks whether students can (a) write Rule 2 as 'pass Maths → pass Computing', (b) chain Rule 2 into Rule 3 to show that passing both Physics and Maths forces all three to be passed, creating a contradiction, and (c) confirm the other three options by finding at least one valid combination that matches each.
Four rules constrain who can pass/fail three subjects. There are only 8 possible pass/fail combinations. Students build a table eliminating invalid rows, then match each answer option to the remaining valid combinations. The impossible option is the one no valid combination can match.
Best approach: List all 8 possible pass/fail combinations for three subjects. Apply each rule as a filter: eliminate any row that breaks a rule. You should end up with exactly 3 valid rows: (Fail,Fail,Pass), (Fail,Pass,Pass), (Pass,Fail,Pass). Check each option: B (Pass Physics + Maths) maps to (Pass,Pass,Fail) or (Pass,Pass,Pass) — both eliminated. B is impossible.
Question
In end-of-year tests, the following results were achieved by students taking Maths, Physics and Computing:
- Everyone who passed Physics also passed at least one of the other two subjects.
- No one who passed Maths failed Computing.
- No one passed all three subjects.
- No one failed all three subjects.
Which one of the following is not possible?
- ALuca failed Physics and Maths.
- BLuca passed Physics and Maths.
- CLuca passed Physics and Computing.
- DLuca passed either only Maths or only Computing.
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15 cards, 3 shapes, numbers 1–9, no two identical. One constraint: only the number 7 appears in both a square and a circle. Which statement must be true? The answer requires working out the maximum possible for squares and circles combined — then subtracting.
'What must be true?' questions involving counting constraints and set overlaps appear regularly on NSW Selective TS. The key skill is finding the ceiling on one group (squares + circles ≤ 10) to establish the floor for another (triangles ≥ 5). This max-then-subtract approach works whenever two groups share a limited overlap.
The examiner tests whether students can (a) translate the 'only 7 is shared' constraint into a cap on squares + circles, (b) use subtraction to get a minimum for triangles, and (c) see that options C and D don't have to be true because squares or circles individually could be very small.
A fixed total is split among three categories with a constraint limiting overlap between two of them. Finding the maximum for those two (using the overlap constraint) gives the minimum for the third. The correct answer states that minimum as 'at least N'.
Best approach: Step 1: Count how many numbers can appear in both squares and circles (only 7 → at most 1 overlap). Step 2: Cap squares + circles = 2 (both 7-cards) + 8 (other numbers, each in at most one of square or circle) = 10. Step 3: Triangles ≥ 15 − 10 = 5. Match to Option B.
Question
Each card in a set of fifteen cards has one of three shapes on it: a triangle, a square or a circle. Inside the shape a number from 1 to 9 is written. No two cards are identical.
The only number that appears in both a square and a circle is 7.
Which one of the following statements must be true?
- AEach shape appears on five cards.
- BThere are at least five cards with triangles on them.
- CThere are at least five cards with squares on them.
- DThere are at least five cards with circles on them.
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Sam needs to impress the music teacher to get into the band. Sara needs Sam in the band to have any chance of persuading Rhiannon to attend. Sam doesn't practice hard enough. Which scenario is completely impossible?
'What cannot be true?' with a multi-step necessary condition chain is a high-difficulty pattern on NSW Selective TS. The key is identifying the chain: NOT impress teacher → NOT in band → NOT Rhiannon comes. The impossible option tries to insert a conclusion that directly contradicts the end of this chain.
The examiner tests whether students can (a) recognise that 'only chance' creates a necessary condition (NOT Sam in band → NOT Rhiannon comes), (b) chain it with the impressing-teacher requirement (NOT impress → NOT in band), and (c) see that Options A, B, D each break at a permitted weak link (chance ≠ certainty), while Option C breaks an airtight link.
A prose scenario contains two nested necessary conditions forming a three-step chain. One option tries to break the last airtight link of the chain (claiming the final effect doesn't follow from the cause). The other options each involve links that are merely possible but not guaranteed, making them genuinely possible.
Best approach: Extract the two key rules: (1) NOT impress teacher → NOT in band. (2) NOT in band → Rhiannon won't come. Chain them: NOT impress → Rhiannon won't come. Then check which option says NOT impress AND Rhiannon does come — that's the impossible one (Option C). Verify the other options by checking they break only 'chance' links, not 'certain' links.
Question
Sara wants to persuade her cousin Rhiannon to come to the school play. Her only chance of persuading her is if Sara's brother, Sam, is playing in the school band. The problem is, it's very hard to get accepted into the band, since the standard is very high. Even some very talented musicians have been turned away. You need to really impress the music teacher at audition to stand a chance. Sam does not practice hard enough to get to that kind of level.
If the above information is correct, which one of the following is not possible?
- ASam impresses the music teacher at audition but is not invited to join the band.
- BSam practices hard but does not impress the music teacher at audition.
- CSam does not impress the music teacher at audition but Rhiannon still comes to the show.
- DSam is accepted into the band but Rhiannon does not come to the show.
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Three switches, four lights. Each switch flip toggles its lights. All start off. Which of the four statements must always be true? The key insight: Red and Green share the same two switches — so they're permanently in sync.
Toggle-switch 'what must be true?' questions appear in NSW Selective TS Deductive Reasoning. The approach is always: (a) map each light's controlling switches, (b) notice any lights that share the exact same set of controllers — those always match, and (c) enumerate the 2^n states to verify the other options are possible.
The examiner tests whether students can (a) recognise that Red and Green share the same controllers (Switch 1 and Switch 2), making them always in sync, (b) verify Options A, B, C by finding a state where each claim is false, and (c) confirm Option D by checking all 8 states or using the shared-controllers insight.
Switches toggle sets of lights. Starting from all-off, enumerate all possible states. Options claim that certain light combinations are impossible. The correct answer identifies a combination that is truly impossible across all 8 states, while the other three have at least one state where they occur.
Best approach: Build a truth table of all 8 switch combinations (S1, S2, S3 each 0/1). Compute each light state using XOR logic. Check each option: find a row that disproves A, B, C (all possible), then confirm D never has R=1 and G=0 (they share the same controllers). Alternatively, spot immediately that R and G share Switch 1 and Switch 2 — they must always match.
Question
Three switches are connected to a set of four lights. When a switch is changed, each of the lights that it controls turns on (if it was off) or off (if it was on).
Switch one controls the red and green lights. Switch two controls the red, green and blue lights. Switch three controls the blue and yellow lights.
If all three switches are off then all four lights are off.
Which one of the following is true?
- AIt is not possible to have all four lights on.
- BThe blue light cannot be on when the yellow light is on.
- CThe green light cannot be on when the blue light is on.
- DThe red light cannot be on when the green light is off.
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Four students rate English, History and Maths. Four clues constrain their rankings. Some students' rankings are completely fixed by the clues; others have flexibility. To find the maximum who could like maths best, lock in the fixed ones and then choose the best arrangement for the flexible ones.
'Maximum/minimum count from partial rankings' is a high-difficulty NSW Selective TS pattern. Students must (a) deduce which rankings are fully determined, (b) identify which students have flexibility, and (c) choose the arrangement for flexible students that maximises (or minimises) the target count.
The examiner tests whether students can (a) use 'Only Gemma liked English > History' to set H > E for all others, (b) combine this with Clue 1 to fix Emily's ranking as M > H > E, (c) combine H > E with Clue 4 to fix Gemma's ranking as E > H > M (maths last), and (d) recognise Wesley and Rohit can each choose M > H > E, giving a maximum of 3.
Multiple clues constrain a group's relative preferences. Some individuals end up with completely fixed rankings; others retain one or more possible orderings. A 'maximum' or 'minimum' question asks you to optimise over the flexible individuals.
Best approach: Step 1: Apply the 'Only Gemma' clue — it fixes H > E for Emily, Wesley, Rohit. Step 2: Combine with Emily's clue to fix M > H > E. Step 3: Combine E > H with Clue 4 (no history last) to fix Gemma at E > H > M. Step 4: Wesley and Rohit have English last and can freely choose M > H > E. Maximum = Emily + Wesley + Rohit = 3.
Question
Four students were comparing how much they enjoyed English, history and maths.
Emily liked maths more than history. Only Gemma liked English more than history. Wesley and Rohit both liked maths more than English. No one liked history the least.
What is the maximum number of students who could have liked maths the most?
- A1
- B2
- C3
- D4
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Five friends have either blue or brown eyes and each enjoy two activities. Two conditional rules link eye colour to activities. Q doesn't read → Q can't have brown eyes → Q has blue eyes. S only likes drawing (plus one more) → in every scenario, S ends up with blue eyes too. The key move is the contrapositive.
'What must be true?' questions with attribute grids and conditional rules are a difficult band NSW Selective TS type. The contrapositive (doesn't read → not brown → blue) must be applied without being confused by the many unknowns (R, T's attributes). Students who try to enumerate all arrangements waste time; those who spot the contrapositive finish in under 2 minutes.
The examiner tests whether students can (a) identify Q as not a reader (piano + fishing), apply the Rule 1 contrapositive to get Q = blue eyes; (b) handle S in both scenarios (S fishes → doesn't read → blue; S doesn't fish → non-fisher has blue eyes) and get the same result; (c) reject A (could have ≥3 blue), C (Q is blue, not brown), and D (T might not read if T is the blue-eyed non-fisher who likes piano + drawing).
People have an attribute (eye colour) and exactly two activities from a fixed set. Two conditional rules link attribute to activity. Some people's activities are fully known; others only partially known. The question asks which statement MUST be true. Apply contrapositive to those whose activities are fully known.
Best approach: Step 1: Write Rules 1 and 2 and their contrapositives. Step 2: For each person with known activities, check if they clearly lack the 'reading' activity. If yes, apply the contrapositive → blue eyes. Step 3: For S, handle both scenarios (fishes / doesn't fish) and show both give blue eyes. Step 4: Cross-check each option against these deductions.
Question
P, Q, R, S and T are friends. They all have either blue eyes or brown eyes. They each enjoy two of the following four activities: fishing, reading, playing the piano and drawing.
P likes reading and fishing. Q likes playing the piano and fishing. S likes drawing. Everyone likes fishing except one person with blue eyes. Everyone with brown eyes likes reading.
Which one of the following statements must be true?
- AThere are more people with brown than blue eyes in the group.
- BQ and S have blue eyes.
- CP and Q have brown eyes.
- DT likes reading.
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Someone is hiding in one of three rooms. Each door has two statements — but at most one per door can be false. Room 2 breaks the rule immediately. Room 1 forces a name contradiction. Only Room 3 survives. This is pure case-elimination logic at its sharpest.
Truth/falsity constraint puzzles with hidden-entity setups appear in the very hardest section of NSW Selective TS — they are rare but high-reward questions that separate top scorers from the rest.
The examiner tests systematic case-elimination: can students apply a truth constraint to each possible scenario, identify which scenarios are impossible (via rule violations or contradictions), and then correctly interpret what the surviving scenario forces to be true?
Two or three locations each have two statements. A constraint limits how many can be false per location. Students test each location as the 'answer', check statements for truth/falsity, and eliminate any location that violates the constraint or creates a logical contradiction. The surviving location is the answer.
Best approach: Create a table with one column per room. For each 'Person is in Room X' hypothesis, go through every statement on every door and mark TRUE/FALSE. Flag any door with two FALSE statements (rule violation) or any pair of conclusions that contradict each other. Rule out that room. The room left standing is the answer. Then check the options: only pick something the surviving scenario FORCES to be true — not something that's merely possible.
Question
I am hiding in one of three rooms. On the door of each room I have written two statements, some true, some false. However, no more than one statement on each door is false.
| Room 1 | Room 2 | Room 3 |
|---|---|---|
| My name is Aziz | I am not in this room | My name is Luisa |
| I am not in this room | I am in Room 3 | I am not in Room 1 |
Which one of the following statements must be true?
- AMy name is Aziz.
- BI'm in Room 1.
- CI'm in Room 3.
- DMy name is Luisa.
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Six friends in a circle. Five spatial clues build the seating map. Then a two-move pattern (throw opposite, hand left) repeats three times until Willow holds the bag. The question asks who started. This is the hardest NSW Selective TS format: spatial setup + sequential tracing combined.
'Circular arrangement + pattern tracing' is a top-difficulty NSW Selective TS question type. It appears rarely but always trips students who try to solve it in their head. The key is always: (1) draw the circle first with numbered seats, (2) confirm every clue fits, (3) only then trace the pattern step by step.
The examiner tests whether students can (a) deduce the three opposite pairs from the clues, (b) use 'left = clockwise' in an inward-facing circle, (c) place Max-Catherine-Grace consecutively, (d) confirm Liam between Karri and Willow, and (e) trace two sub-moves per repetition without losing track of the current holder.
People stand in a circle facing inward. Several clues give opposite pairs and adjacency. Then a multi-step pattern is applied repeatedly and the final position is given. You must find the starting position by forward-testing each option (or working backwards).
Best approach: Step 1: Find the three opposite pairs. Step 2: Use 'left=clockwise' to place consecutive neighbours. Step 3: Draw the circle and number every seat. Step 4: For each answer option, trace the two-move pattern 3 times and check if Willow holds it at the end. Only one option works.
Question
Six friends are standing in a circle in the playground, facing inwards. Grace is standing to the left of Catherine and is opposite Willow. Max is facing Karri and is standing next to Catherine. Liam is in between Willow and Karri.
They've been playing a game in which they throw a bean bag to one another in a specific pattern. Someone throws the bean bag to the person opposite. They then hand it to the friend on their left. In the first round, after three repetitions of this pattern Willow is holding the bean bag.
Who was holding the bean bag at the start?
- AGrace
- BKarri
- CWillow
- DCatherine
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