Unit 2
Schedule and Timetable Matching
About this unit
Read complex timetables and match people, activities, or events to available slots. You will cross-reference preferences, availabilities, and constraints to find the single valid option that satisfies every condition simultaneously.
What types of questions will you face?
- 1Given a timetable and a person's preferences/dislikes, identify which days they will or won't attend
- 2Select the one activity a student can attend given a required schedule and exclusions
- 3Cross-reference multiple schedules to find the only day all constraints are met
- 4Determine the earliest or latest slot that fits all given requirements
- 5Identify which event/option satisfies a set of inclusion and exclusion criteria
Skills you will build
- Reading multi-column timetable tables accurately
- Applying inclusion and exclusion rules simultaneously
- Using elimination to narrow down valid options
- Tracking multiple people's constraints at once
- Handling "only attend if at least one liked option is available" style conditions
By the end of this unit, you will be able to
- Navigate any complex timetable and pinpoint the valid slot instantly
- Apply multiple simultaneous constraints to identify the unique solution
- Quickly eliminate options that violate any single rule
- Find the intersection of multiple schedules under real-world constraints
Difficulty profile
Questions are Very Easy to Easy. Success depends on careful table-reading and systematic elimination rather than advanced reasoning.
Exam tip: Schedule and Timetable Matching
Go column by column (or day by day) and mark each slot as valid or invalid. The answer is the only slot left standing after all constraints are applied.
Sample Questions
Schedule and Timetable Matching questions are a staple of OC Thinking Skills — and they are highly systematic once you know the pattern. Let's begin with the most common variant: given a person's likes and dislikes, find the one day when they won't show up.
This exact format appears in most OC Thinking Skills tests and is frequently placed early in the paper. It rewards students who are thorough rather than quick — missing a single cell in the table is all it takes to get it wrong.
The examiner is checking whether you can cross-reference a table of options against a set of personal preferences and correctly identify the day where no liked option appears — not just reduce the number of options, but find the one day with zero qualifying choices.
A character will only attend an activity on days when at least one item they enjoy is available. You're given a lookup table of items and their days, told what the person dislikes, and asked which day they skip entirely.
Best approach: Start by marking what the person LIKES — it's usually faster to identify the small dislike list and mentally exclude those. Then scan each day in the table: the moment you find at least one liked item, that day is "safe". The one day with zero liked items is your answer.
Question
After school, Zoe will only attend book club on a day when at least one genre she enjoys is featured. She dislikes science fiction and mystery.
| genre | days featured |
|---|---|
| history | Thursday, Friday |
| science fiction | Monday, Tuesday, Thursday |
| mystery | Tuesday, Wednesday, Friday |
| adventure | Monday, Wednesday, Saturday |
On which weekday will Zoe not attend book club?
- AMonday
- BTuesday
- CWednesday
- DThursday
- EFriday
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Sometimes the question is not about days or timetables at all — it is about people. Given a group of friends with different tastes, can you find the single option they all agree on? This is the simplest form of preference-matching: build a checklist and look for the column that is all ticks.
Preference intersection questions appear regularly in OC Thinking Skills, often early in the paper. They look easy but students rush them and miss a constraint — the safest approach is always to build a column for each person before deciding.
The examiner is testing whether you can track multiple sets of likes and dislikes at the same time without mixing them up. The key trap is misreading one person's rule (e.g. confusing "does not like cartoons" with "likes all movies except cartoons").
Several friends or people each have a stated preference — some positive ("only likes X and Y"), some negative ("likes all except Z"). You must find the one option that satisfies every single person.
Best approach: Write one row per person. For each movie (or activity) type, tick if they like it and cross if they don't. The answer is the column where every row has a tick. Do NOT guess — one missed cross on any row means a wrong answer.
Question
Four friends want to go to the movies. There are four kinds of movies showing: cartoon, comedy, drama and action.
Andrew likes all movies except dramas and action.
Rishi and Audrey only like comedies and dramas.
Yifan would like to watch any movie so long as it is not a cartoon or an action movie.
Which kind of movie would all four friends like to see?
- Acomedy
- Baction
- Ccartoon
- Ddrama
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Inge and Finn first meet on a Tuesday. Eight days later they meet again. Four days after that they meet a third time. Which day of the week is that third meeting? This is the simplest form of day-counting arithmetic: start on a known day, add one number, add another, and read off the result.
Day-counting questions with a two-step offset are one of the most common OC TS question types. They appear on nearly every official practice paper and are worth getting right quickly. Students who count seven as "one full week back to the same day" and then count the remainder reach the answer in seconds.
The examiner is testing whether students can add multi-day gaps to a named day of the week without losing track. The trap options (Tuesday and Wednesday) catch students who either stop after the first gap or confuse "8 days later" with "8 days from Monday (the next day)" instead of counting correctly from Tuesday.
A short paragraph gives a starting day and one or two subsequent offsets (e.g. "8 days later", "4 days after that"). The question asks what day of the week one specific meeting falls on. Four answer options are all days of the week — often including the start day and the next day to catch off-by-one errors.
Best approach: Start from the given day and count forward. A clean trick for large offsets: subtract multiples of 7 first (since 7 days = one full week = same day), then count the remainder. For "8 days later from Tuesday": 8 = 7 + 1, so one week = Tuesday again, +1 more = Wednesday. For "4 days later from Wednesday": Wednesday → Thursday → Friday → Saturday → Sunday. Write the chain out rather than doing it in your head.
Question
Inge and Finn first met on a Tuesday.
They met again 8 days later.
They then met for the third time 4 days later.
On which day did Inge and Finn meet for the third time?
- ATuesday
- BWednesday
- CSaturday
- DSunday
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Now let's step up to a more demanding variant — one where you must satisfy an additional mandatory constraint on top of your available days. This is where many students go wrong by not reading the extra requirement carefully enough.
Constrained matching questions like this appear regularly in the middle-to-upper difficulty range of OC TS tests. The mandatory condition is the key twist that separates this type from straightforward preference matching.
The examiner wants to see whether you can handle a two-step problem: first, honour the mandatory constraint by assigning it to the only day it can occupy on your schedule, and then check which other clubs are still possible with the days that remain.
You're given a set of available days, a table of clubs or activities with their meeting days, and a rule that one specific club MUST be included in your plan. You need to identify which other club cannot fit once the mandatory one locks in a day.
Best approach: Place the mandatory club first — find which of your available days it meets on, lock that day in. Then work through each remaining club and check whether it has any meeting day left among your still-free days. The club whose only possible day is already taken is your answer.
Question
A library lists when each reading club meets:
| Club | Days |
|---|---|
| fiction | Monday, Thursday |
| biography | Tuesday, Wednesday |
| poetry | Tuesday, Saturday |
| science | Wednesday, Thursday |
| history | Monday, Friday |
You want to attend on Monday, Wednesday, and Saturday. One of those sessions must be biography.
Which club can you not fit into that plan?
- Afiction
- Bhistory
- Cscience
- Dpoetry
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Here is a classic Schedule and Timetable question with a twist — you have three available days AND a mandatory sport that must be included. The trick is to lock in the mandatory sport first, then check which other sports can fill your remaining free days.
This "mandatory-plus-check" format appears regularly in OC Thinking Skills tests. It is easy to get wrong if you try to check all sports at once instead of fixing the mandatory one first.
The examiner wants to see whether you can handle two constraints at the same time: a set of available days, and a mandatory activity that locks in one of those days. Once the mandatory slot is fixed, you check each remaining option against your still-free days.
A table lists activities and the days they run. You are told which days you can attend and that one specific activity must be included. You must find the activity that can never fit into your plan.
Best approach: Start with the mandatory activity. Find which of your available days it can run on, then lock that day in. With your remaining free days, go through every other activity — any activity whose available days are all blocked is the answer.
Question
A community club offers the following sports:
| sport | days available |
|---|---|
| netball | Monday, Thursday |
| boxing | Monday, Friday |
| football | Tuesday, Wednesday |
| swimming | Wednesday, Thursday |
| tennis | Tuesday, Friday |
I want to do a sport on a Monday, Wednesday and Friday.
One of my sports must be football.
Which sport will I not be able to do?
- Anetball
- Bboxing
- Cswimming
- Dtennis
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A dentists' surgery is open for 9 hours, each dentist takes a 60-minute lunch break, each appointment is 20 minutes, and there are 3 dentists. How many appointments can they fit in a day? This is a clean, multi-step capacity question — the kind that trips up students who rush and forget to subtract the lunch break.
Capacity and scheduling calculation questions appear in almost every OC TS exam. They are structured around a real-world scenario (opening hours, break times, slot durations) and test whether students can carry out a small chain of arithmetic steps in the right order. The most common error is skipping the lunch-break subtraction, which lands students on the trap answer 81.
The examiner is testing whether students can: (1) convert opening hours to minutes, (2) subtract non-working time, (3) divide by the slot length, and (4) multiply by the number of workers — all in sequence without losing track. Each wrong answer corresponds to a specific arithmetic mistake, so the options are carefully designed traps.
A workplace (clinic, bus route, shop) has fixed opening hours. Each worker has one or more break periods and serves customers in fixed-length time slots. You must find the total capacity for the day. The key steps are always: total time → subtract breaks → divide by slot length → multiply by number of workers.
Best approach: Work through the four steps in order and write down each result: (1) total minutes open, (2) minutes each worker is actually available, (3) appointments per worker, (4) total appointments for all workers. Never skip step 2 — the lunch break is the deliberate trap. Always double-check your hours-to-minutes conversion: 8am to 5pm is 9 hours, not 8 or 10.
Question
A dentists' surgery opens at 8:00 am and closes at 5:00 pm each day. Each appointment is 20 minutes and every dentist has a 60-minute lunch break but no other breaks.
Three dentists work in the surgery.
What is the maximum number of appointments that can be made in the surgery in a day?
- A63
- B72
- C81
- D90
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Shiro sees everyone in Chromatica wearing the same colour. He checks the festival colour table — and is still not sure which festival it is. That "still not sure" detail is the whole key to the question. This puzzle teaches one of the most useful table-reading skills: recognising that ambiguity means the value must appear more than once in the data.
Table-reading questions with an "ambiguity" or "still unsure" condition appear regularly in OC TS. They combine simple data lookup with a logical layer: if a person cannot determine the answer, what does that tell you about the data? This type of question rewards students who think about what the data excludes, not just what it includes.
The examiner is testing whether students can use an "uncertainty" clue in reverse — if Shiro is still unsure, yellow is automatically eliminated because it uniquely identifies one festival. Students who only look up colours without asking "which ones would leave him unsure?" will choose option D (all three colours), which is the most common wrong answer.
A table maps items to attributes (festival to colour, train to platform, student to sport). A character observes one attribute and cannot determine which item it corresponds to, even after checking the table. You must identify which attribute values are shared by multiple items (making identification impossible) and which are unique (making identification certain).
Best approach: For each attribute value in the table, count how many items share it. Values shared by 2+ items = ambiguous (Shiro could have seen these). Values shared by only 1 item = unambiguous (Shiro would know for certain — so rule these out). The correct answer lists only the ambiguous values. Any option that includes a unique value (like Yellow here) is wrong.
Question
The Kingdom of Chromatica has five traditional festivals which are held every year. During these festivals, all the citizens of Chromatica wear the same colour. The colours are shown in this table:
| Festival | Colour |
|---|---|
| Chromatican Independence Day | Red |
| The King's Official Birthday | Yellow |
| Women's Day | Blue |
| The Ice Carnival | Blue |
| Chromatican New Year | Red |
Shiro is visiting Chromatica and sees that everyone is wearing the same colour, so he knows they are celebrating a festival, but he doesn't know which one. Even after checking the table above, he's still not sure.
What can we say about the colour that Shiro saw everyone wearing?
- AIt was either red or yellow.
- BIt was either yellow or blue.
- CIt was either blue or red.
- DIt could have been red, yellow or blue.
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Ten students each get two attempts at a 200m sprint. Their "result" is the faster of the two. From a table of 20 times, you need to find who came 3rd. This question builds a crucial skill: deriving a new value from raw data (the result), then ranking all 10 to answer a specific placement question.
Two-attempt competition ranking questions appear in OC TS exams and reward students with careful, systematic table-reading habits. The most common errors are using the wrong attempt (the second attempt instead of the best), or ranking only the four answer options without checking all ten students.
The examiner is testing whether students can apply a stated rule (fastest time counts) across a multi-row table and then rank the derived values correctly. The four answer options are all students with similar times (24.8–25.2 seconds), so students who only check those four and miss that Student 9 (24.5) is 2nd and Student 5 (24.8) is 3rd will arrive at the wrong answer.
A table gives multiple attempts or scores for each competitor. A rule specifies which value counts (e.g. best, average, total). You must apply the rule to each row to get a "result", then rank all results. The question asks for a specific placing (e.g. 3rd, last). The answer options contain several students with close results to maximise confusion.
Best approach: Work through every row in the table, write down the result for each student (the minimum of their two attempts here), then sort all results from smallest to largest. Do NOT only check the four students named in the answer options — you must rank all 10 to know where each one places. Circle or highlight the 3rd value in your sorted list to confirm.
Question
In a competition, 10 students were allowed two attempts at running 200 metres as fast as possible. The fastest time in the two attempts was counted as their 'result'. The attempts for the 10 students are shown in the table.
| student number | attempt 1 (in seconds) | attempt 2 (in seconds) |
|---|---|---|
| 1 | 25.6 | 24.1 |
| 2 | 25.0 | 26.4 |
| 3 | 27.4 | 25.8 |
| 4 | 25.3 | 24.9 |
| 5 | 24.8 | 26.3 |
| 6 | 26.1 | 27.2 |
| 7 | 26.4 | 28.1 |
| 8 | 27.7 | 26.9 |
| 9 | 25.8 | 24.5 |
| 10 | 25.2 | 25.6 |
Which student came 3rd in the competition?
- Astudent 4
- Bstudent 5
- Cstudent 9
- Dstudent 10
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Cecilia only likes lemon and grape juice. A table shows which juices are available on which days. One day has no lemon and no grape — that is the day she will not visit. Simple table filtering, but the "not" in the question catches students who find the days she DOES visit instead.
"Which day will X NOT do Y?" questions with a filter condition appear regularly in OC TS. They combine table reading with a two-step logic: (1) narrow the valid options (only lemon and grape), then (2) find the day where none of the valid options appear. The negation ("not visit") is the most common source of error.
The examiner is testing whether students can apply a preference filter before reading the schedule. Students who simply look for "any juice available on Thursday" (and find orange and apple) will think Thursday is fine — unless they first crossed off the juices Cecilia dislikes.
A paragraph describes someone's preferences or restrictions (e.g. does not like X or Y). A table maps items to days. The question asks which day the person will NOT be able to satisfy their preference. Options are days of the week. One day will have only the excluded items.
Best approach: Start by listing only the things the person likes. Then go through the table and highlight only those rows. Read off which days appear in those highlighted rows — those are the days she will visit. The answer is the day that is NOT in any of the highlighted rows. Check each answer option against your short list to be sure.
Question
After school, Cecilia likes to visit her favourite juice stand to buy a drink. The stand sells four types of juice, which are available on different days. Cecilia does not like apple or orange juice, but she will visit the stand as long as she can buy a drink that she likes.
| juice | days available |
|---|---|
| lemon | Monday and Wednesday |
| orange | Tuesday, Wednesday and Thursday |
| apple | Thursday and Friday |
| grape | Monday, Tuesday and Friday |
On which day will Cecilia not visit the juice stand?
- ATuesday
- BWednesday
- CThursday
- DFriday
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A magic school has a 4-day timetable with 3 classes per day. Wands are needed for spells, charms, and herbs only. This week, Wednesday is cancelled. How many wand-required classes remain? This question layers two filters: first identify which class names need a wand, then remove an entire day's worth of classes before counting.
Multi-filter timetable counting questions appear frequently in OC TS. They combine a subject filter (which classes need equipment) with a schedule exception (one day cancelled, a class moved, etc.). Students who forget to apply the cancellation and count all weeks of wand classes will get 5 instead of 4 — a classic off-by-one error that comes from not re-reading the exception condition.
The examiner is testing whether students can apply two separate conditions at once: (1) only count wand-required classes, and (2) exclude Wednesday's classes this week. Students who forget condition (2) will count Wednesday's spells class and arrive at 5. Students who misidentify which classes need a wand (including broom flight or farsight) will also get the wrong total.
A timetable grid lists subjects for each day and time slot. A rule specifies which subjects require a certain item or meet a certain condition (e.g. need a wand). An exception modifies the schedule for the current week (cancelled day, extra class). You must count how many classes satisfy the condition after applying the exception.
Best approach: First, highlight all wand-required class names in the table: spells, charms, herbs. Then cross out the entire Wednesday column (cancelled). Finally, go through the remaining cells and count only the highlighted ones: Monday spells (1), Tuesday herbs + charms (2), Thursday herbs (1). Total = 4. Do not count the Wednesday spells — that column is struck out.
Question
In a school for young magicians, the weekly timetable is the following:
| Monday | Tuesday | Wednesday | Thursday | |
|---|---|---|---|---|
| 9:00–10:00 | stars & sky | potions & poisons | spells | herbs |
| 10:00–11:00 | farsight | herbs | broom flight | stars & sky |
| 11:00–12:00 | spells | charms | farsight | broom flight |
The young magicians need their magic wand for three classes: spells, charms, and herbs. There are no classes on Fridays.
This week, the classes on Wednesday are cancelled due to a competition.
For how many classes do the young magicians need their wands this week?
- A2
- B3
- C4
- D5
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History only appears in List 1, so it must be your List 1 subject — that immediately locks arts out. Then map English and Science to their remaining possible lists, and check which of the answer options can never be reached from any free list.
Multi-list constrained-choice questions (pick one from each list, some already committed) appear regularly in OC TS at easy-to-medium difficulty. Students who try to reason in their head get confused; drawing a quick grid with each scenario takes 30 seconds and guarantees the right answer.
The examiner checks whether students can systematically assign committed subjects to specific lists (locking those lists), then enumerate all remaining valid scenarios to determine which option is permanently blocked.
A student must choose one subject from each of four lists, and has already committed to three subjects. Students must find which of the answer options can never be assigned to any remaining free list under any valid assignment.
Best approach: First, lock subjects that appear in only one list (like history in List 1). Then enumerate the valid scenarios for the remaining committed subjects. Collect all possible "4th subject" values across every scenario. The option not in that collection is the answer.
Question
Next year at school I need to choose four subjects to study.
I have to choose one subject from each of the following lists:
List 1: arts, geography, history, PE
List 2: English, maths, design, health
List 3: English, geography, science, technologies
List 4: maths, science, PE, technologies
I know that I want to study English, history and science.
Which one of the following can I not choose as my final subject?
- Aarts
- Bgeography
- Chealth
- DPE
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John needs a red and a green robot. He can buy a pack of three, and his friend will swap a pink robot for a green one. Which pack lets him walk away with both colours he needs? The trick is recognising the two-step route: get red from the pack directly, and use the pink in the same pack to trade for green.
Two-step resource acquisition questions — where you combine a direct purchase with a secondary exchange — appear regularly in OC TS. They test whether students can track multiple conditions simultaneously. The most common mistake is finding a pack with ONE of the needed items and stopping there, without checking whether the second need can be met through the trade.
The examiner is testing whether students can apply two conditions at once: (1) the pack must contain red, and (2) the pack must contain pink (to trade for green). Pack 1 has red but no pink, so it fails condition 2. Pack 3 has green and pink but no red — students who see 'green is in the pack' stop early and miss that red is still needed. Pack 4 has pink but no red. Only Pack 2 satisfies both conditions.
A table lists options (packs, bundles, selections) and what each contains. A separate trade or exchange rule lets you convert one item into another. You need to find the single option that satisfies ALL the requirements — both through direct contents and through the available trade. Read the requirements first, then check each option systematically.
Best approach: List what you need: red and green. Note the trade: pink → green. Then re-frame the question: you need a pack with red AND (green OR pink). Check each pack against that combined condition. Pack 1: red ✓, no pink/green ✗. Pack 2: red ✓, pink ✓ (trade for green) ✓ — done. You don't need to check packs 3 and 4 once you find the answer, but always check that no other pack also works (here, none do).
Question
John is collecting a set of toy robots based on his favourite television program. The robots come in different colours and John still needs the red and green robots to complete his set. The local shop has an offer where they will sell any of the following packs of three robots for $10.
| pack | robot 1 | robot 2 | robot 3 |
|---|---|---|---|
| pack 1 | red | blue | yellow |
| pack 2 | red | yellow | pink |
| pack 3 | green | pink | purple |
| pack 4 | blue | orange | pink |
John has a friend who has a spare green robot and will swap it for a pink robot.
Which pack should John buy to be able to complete his set?
- Apack 1
- Bpack 2
- Cpack 3
- Dpack 4
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