Unit 4 · Statistics and Probability
Average of Six Numbers — Find the Missing Value
Lesson 1 of 6
Let's start with the single most important insight in every OC MR averages question: an average is just a sum in disguise. The moment you realise you can always recover the total by multiplying the average by the count, a whole family of questions becomes straightforward.
Mean and averages questions appear in almost every OC MR paper — usually one or two per test, spread across easy and difficult. The easy variants involve a single group; the harder ones split the group in two and ask you to work back and forth between both halves.
The examiner is checking whether you know that mean × count = total. Students who try to reason about averages directly — without converting to totals first — consistently pick the wrong answer on split-group questions.
You are told the average of a full group (e.g. 6 numbers averaging 18) and the average of one part of it (e.g. the first 3 average 14). You must find the average of the remaining part. The numbers are deliberately chosen so that trial-and-error is slow — the total-sum method is the only clean path.
Best approach: Step 1: Multiply the full group average by its count to get the grand total. Step 2: Multiply the sub-group average by its count to get the sub-group total. Step 3: Subtract to find the other sub-group's total. Step 4: Divide by that sub-group's count. Four arithmetic steps — no guessing needed.
Question
The average of 6 numbers is 18. If the average of the first 3 numbers is 14, find the average of the other 3 numbers.
Select an answer to see the explanation.
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