Mathematical Reasoning
Three different numbers are chosen from the numbers 2, 4, 7 and 9.
Question 1 · Multiple choice
Question
Three different numbers are chosen from the numbers 2, 4, 7 and 9.
They are then added together.
Options
Which of these statements is/are correct?
Statement 1: The total is always greater than 12.
Statement 2: The total can be a multiple of 9.
Statement 3: The total cannot be even.
- A.none of them
- B.statement 2 only
- C.statement 3 only
- D.statements 1 and 2 only
- E.statements 1 and 3 only
Correct answer
Explanation
The method: list every combination, then test each statement
Choose 3 different numbers from {2, 4, 7, 9}. There are exactly 4 ways to do this:
| Combination | Sum |
|---|---|
| 2 + 4 + 7 | 13 |
| 2 + 4 + 9 | 15 |
| 2 + 7 + 9 | 18 |
| 4 + 7 + 9 | 20 |
All possible totals: 13, 15, 18, 20
Statement 1: "The total is always greater than 12."
"Always" means: check every total — even one exception would make it false.
- 13 > 12 ✓, 15 > 12 ✓, 18 > 12 ✓, 20 > 12 ✓
Every total is greater than 12 → Statement 1 is TRUE ✓
Statement 2: "The total can be a multiple of 9."
"Can be" means: does at least one combination give a multiple of 9?
Multiples of 9: 9, 18, 27 …
18 appears in the list (from 2 + 7 + 9) → Statement 2 is TRUE ✓
Statement 3: "The total cannot be even."
"Cannot be even" means: none of the totals should be even. But:
18 and 20 are both even — so the total CAN be even → Statement 3 is FALSE ✗
Answer: statements 1 and 2 only
Repeatable checklist
-
Write ALL combinations (leave nothing out; use a system like "smallest first").
-
Calculate each sum.
-
"Always" → every single value must fit (one exception = FALSE).
-
"Can be" → just one value needs to fit (one example = TRUE).
-
"Cannot be" → look for any counterexample (one counterexample = FALSE).