Mathematical Reasoning Mock Test 15: 2027 NSW Selective Format

Build fluency with multi-step problems, diagrams, and data interpretation in our 35-question mock test—aligned to the Janison-style NSW Selective Mathematical Reasoning paper.

Duration

40 Minutes

Format

2027 NSW Format

Questions

35 multiple-choice

Level

Official Selective Test Level

Skills Covered in this Test

This mock test mirrors the official weightings of the NSW Department of Education exam.

The breakdown

  • Profit & Loss: Revenue, cost, and margin reasoning in scenarios.
  • Percentages: Discounts, changes, and comparisons expressed as percent.
  • Decimals: Place value, rounding, and decimal operations under time pressure.
  • Multi-step Word Problems: Breaking down scenarios into equations and checking reasonableness.
  • Mental Arithmetic: Fast, accurate calculation without a calculator.
  • Ratios: Part-part and part-whole relationships in applied settings.

Sample Questions from Test 15

The first two questions of this mock test (same order and wording as the timed exam).

Mathematical Reasoning

Leo has amber, coral, indigo, and lime marbles in a bag.

Question 1 · Multiple choice

Question

Leo has amber, coral, indigo, and lime marbles in a bag.

There are twice as many indigo marbles as amber marbles.

He takes one marble out without looking.

  • The probability it is amber is 0.2.
  • The probability it is coral is 0.35.

Options

What is the probability that Leo takes out a lime marble?

  • A.0.1
  • B.0.3
  • C.0.05
  • D.0.5
  • E.0.95

Correct answer

C.0.05

Explanation

Big idea: All probabilities for one pick must add up to 1 (100%).

Step 1 — Indigo from the "twice as many" rule

If there are twice as many indigo marbles as amber marbles, then:

P(indigo) = 2 × P(amber) = 2 × 0.2 = 0.4

Step 2 — Add the probabilities you know

ColourProbability
Amber0.2
Coral0.35
Indigo0.4
Total so far0.95

Picture the four colours filling the whole probability bar from 0 to 1:

0         0.2      0.55       0.95 1.0
|──amber──|──coral──|──indigo──|lime|
   0.20      0.35      0.40    0.05

Step 3 — Lime is what is left

P(lime) = 1 − 0.95 = 0.05

Answer: 0.05

Repeatable checklist

  1. Turn "twice as many" into double the probability (same bag, one pick).

  2. Add every probability you know.

  3. Subtract from 1 to find the last colour.

Common traps

  • 0.1 — answer from the Janison question (different numbers).
  • 0.95 — added the three known probabilities but forgot to subtract from 1.
  • 0.3 — used coral's probability or mixed up colours.
  • 0.5 — doubled the wrong probability.

Mathematical Reasoning

Dana, Evan and Fern shared a granola bar divided into 5 equal pieces.

Question 2 · Multiple choice

Question

Dana, Evan and Fern shared a granola bar divided into 5 equal pieces.

  • Dana ate 1/5 of the bar.
  • Evan ate 2/5 of the bar.
  • Fern ate the rest.

Options

Which of the following statements are correct?

Statement 1: Fern ate less than half of the bar.

Statement 2: Dana ate more than one quarter of the bar.

Statement 3: Dana and Evan ate less than three quarters of the bar altogether.

  • A.statement 1 only
  • B.statement 2 only
  • C.statement 3 only
  • D.statements 1 and 2 only
  • E.statements 1 and 3 only

Correct answer

E.statements 1 and 3 only

Explanation

Step 1 — How much did Fern eat?

The whole bar is 5/5.

Dana + Evan: 1/5 + 2/5 = 3/5

Fern (the rest): 5/5 − 3/5 = 2/5

Whole bar (5 equal pieces):
┌──────┬─────────────┬─────────────┐
│ Dana │    Evan     │    Fern     │
│  1/5 │     2/5     │     2/5     │
└──────┴─────────────┴─────────────┘

Benchmarks:
  Half (½)  = 2.5 pieces   →  Fern's 2 pieces < half     ✓
  Quarter(¼) = 1.25 pieces →  Dana's 1 piece  < quarter  ✗
  ¾ of bar  = 3.75 pieces  →  Dana+Evan = 3 pieces < ¾   ✓

Step 2 — Test each statement

Use the same denominator when comparing (often 10 or 20 works well).

PersonFractionAs tenths
Dana1/52/10
Evan2/54/10
Fern2/54/10
Together Dana + Evan3/56/10

Statement 1: "Fern ate less than half of the bar."

  • Half = 1/2 = 5/10
  • Fern = 4/10
  • 4/10 < 5/10 → True

Statement 2: "Dana ate more than one quarter of the bar."

  • One quarter = 1/4 = 5/20
  • Dana = 1/5 = 4/20
  • 4/20 is not more than 5/20 → False

Statement 3: "Dana and Evan ate less than three quarters of the bar altogether."

  • Three quarters = 3/4 = 15/20
  • Dana + Evan = 3/5 = 12/20
  • 12/20 < 15/20 → True

Answer: statements 1 and 3 only

Repeatable checklist

  1. Add the given fractions; subtract from 1 (or from 5/5, 6/6, etc.) for "the rest".

  2. Rewrite fractions with a common denominator before comparing.

  3. Test each statement separately — do not assume two true statements must be "1 and 2".

Traps in the options

  • Statement 2 only — 1/5 looks small but is less than 1/4.
  • Statements 1 and 2 only — statement 2 is false.

Core Competencies

3D NetsAlgebraic SubstitutionsAngle PropertiesArea & PerimeterCartesian CoordinatesDecimalsFractionsGraph InterpretationInverse OperationsLogical DeductionMean, Median & ModeMental ArithmeticMulti-step Word ProblemsNumber SequencesOrder of OperationsPercentagesPrime NumbersProbability LogicProfit & LossRatiosReflection & RotationSpeed, Distance, TimeSquare & Cube NumbersSymmetryTime & CalendarsUnit ConversionsVenn DiagramsVolume & Capacity

Prepare with Precision

  • Sharpen accuracy on multi-step and diagram-based items.
  • Get comfortable with the Janison-style interface.
  • Identify topics to revisit before exam day.

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