Mathematical Reasoning Mock Test 13: 2027 NSW Selective Format

Build fluency with multi-step problems, diagrams, and data interpretation in our 35-question mock test—aligned to the Janison-style NSW Selective Mathematical Reasoning paper.

Duration

40 Minutes

Format

2027 NSW Format

Questions

35 multiple-choice

Level

Official Selective Test Level

Skills Covered in this Test

This mock test mirrors the official weightings of the NSW Department of Education exam.

The breakdown

  • Cartesian Coordinates: Plotting, distance, and reading coordinates from grids.
  • Angle Properties: Using angles on lines, triangles, and parallel lines.
  • 3D Nets: Visualising folded and unfolded solid shapes.
  • Area & Perimeter: Measuring and comparing plane figures in word problems.
  • Reflection & Rotation: Transformations and image positions on grids.
  • Symmetry: Recognising reflection and rotational symmetry in diagrams.

Sample Questions from Test 13

The first two questions of this mock test (same order and wording as the timed exam).

Mathematical Reasoning

Mao had 360 more rubber seeds than Sun. When Sun gave 46 rubber seeds to Mao, Mao had 5 times as many rubber …

Question 1 · Multiple choice

Question

Mao had 360 more rubber seeds than Sun. When Sun gave 46 rubber seeds to Mao, Mao had 5 times as many rubber seeds as Sun. How many rubber seeds did Mao have at first?

Options

  • A.439
  • B.469
  • C.499
  • D.549
  • E.519

Correct answer

E.519

Explanation

Step 1: Set up variables

Let Sun's seeds at the start = S

Then Mao's seeds = S + 360 (Mao had 360 more)

Step 2: Apply the transfer (Sun gives 46 to Mao)

After the transfer:

  • Sun has: S − 46
  • Mao has: (S + 360) + 46 = S + 406

Step 3: Use the 5-times condition

After the transfer, Mao has 5 times as many as Sun:

S + 406 = 5 × (S − 46)

S + 406 = 5S − 230

406 + 230 = 5S − S

636 = 4S

S = 636 ÷ 4 = 159

Step 4: Find Mao's original seeds

Mao at first = S + 360 = 159 + 360 = 519

Check: After transfer: Sun = 113, Mao = 565. 565 = 5 × 113 ✓

Answer: Mao had 519 seeds at first

Mathematical Reasoning

Nia saves into a money box.

Question 2 · Multiple choice

Question

Nia saves into a money box.

At the end of Monday it holds $10.

At the end of Wednesday it holds $28.

At the end of Friday it holds $76.

She puts the same amount in on Tuesday, Wednesday and Friday.

How much does she put in on Thursday?

Options

  • A.$25
  • B.$29
  • C.$32
  • D.$39
  • E.$41

Correct answer

D.$39

Explanation

Step 1: Find how much Nia deposits on each of Tuesday, Wednesday and Friday

Let the amount she deposits on Tuesday, Wednesday and Friday = $w each.

At end of Monday: $10 After Tuesday (+w): $10 + w After Wednesday (+w): $10 + w + w = $10 + 2w

We know this equals $28:

10 + 2w = 28

2w = 18

w = $9 per day (on Tuesday, Wednesday and Friday)

Step 2: Find Thursday's deposit

After Wednesday: $28

Let Thursday deposit = $t

After Thursday: $28 + t

After Friday (+$9): $28 + t + 9 = $76

37 + t = 76

t = $39

Check:

  • Mon end: $10
  • Tue end: $10 + $9 = $19
  • Wed end: $19 + $9 = $28 ✓
  • Thu end: $28 + $39 = $67
  • Fri end: $67 + $9 = $76 ✓

Answer: Nia deposits $39 on Thursday

Core Competencies

3D NetsAlgebraic SubstitutionsAngle PropertiesArea & PerimeterCartesian CoordinatesDecimalsFractionsGraph InterpretationInverse OperationsLogical DeductionMean, Median & ModeMental ArithmeticMulti-step Word ProblemsNumber SequencesOrder of OperationsPercentagesPrime NumbersProbability LogicProfit & LossRatiosReflection & RotationSpeed, Distance, TimeSquare & Cube NumbersSymmetryTime & CalendarsUnit ConversionsVenn DiagramsVolume & Capacity

Prepare with Precision

  • Sharpen accuracy on multi-step and diagram-based items.
  • Get comfortable with the Janison-style interface.
  • Identify topics to revisit before exam day.

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